3cos(2x)+2sin^2(X)=2

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Solution for 3cos(2x)+2sin^2(X)=2 equation: 


Simplifying
3cos(2x) + 2sin2(X) = 2

Remove parenthesis around (2x)
3cos * 2x + 2sin2(X) = 2

Reorder the terms for easier multiplication:
3 * 2cos * x + 2sin2(X) = 2

Multiply 3 * 2
6cos * x + 2sin2(X) = 2

Multiply cos * x
6cosx + 2sin2(X) = 2

Multiply in2s * X
6cosx + 2in2sX = 2

Solving
6cosx + 2in2sX = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2in2sX' to each side of the equation.
6cosx + 2in2sX + -2in2sX = 2 + -2in2sX

Combine like terms: 2in2sX + -2in2sX = 0
6cosx + 0 = 2 + -2in2sX
6cosx = 2 + -2in2sX

Divide each side by '6osx'.
c = 0.3333333333o-1s-1x-1 + -0.3333333333in2o-1x-1X

Simplifying
c = 0.3333333333o-1s-1x-1 + -0.3333333333in2o-1x-1X

Reorder the terms:
c = -0.3333333333in2o-1x-1X + 0.3333333333o-1s-1x-1

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